¿Puede el tamaño de una matriz ser una variable?

Can the size of an array be a variable?

Variable sized arrays are data structures whose length is determined at runtime rather than compile time. These arrays are useful in simplifying numerical algorithm programming. The C99 is a C programming standard that allows variable sized arrays.

In computer programming, a variable-length array (VLA), also called variable-sized or runtime-sized, is an array data structure whose length is determined at run time (instead of at compile time). In C, the VLA is said to have a variably modified type that depends on a value (see Dependent type).

In essence, CUDA arrays are opaque memory layouts optimized for texture fetching. They are one-dimensional, two-dimensional, or three-dimensional and composed of elements, each of which has 1, 2 or 4 components that may be signed or unsigned 8-, 16- or 32-bit integers, 16-bit floats, or 32-bit floats.

Variable Length Arrays in C and C++ Variable length arrays is a feature where we can allocate an auto array (on stack) of variable size. But C++ standard (till C++11) doesn’t support variable sized arrays. The C++11 standard mentions array size as a constant-expression See (See 8.3.

You can declare an array without a size specifier for the leftmost dimension in multiples cases: as a global variable with extern class storage (the array is defined elsewhere), as a function parameter: int main(int argc, char *argv[]) .

If there is, how can I create that array? – Quora. You cannot have an actually infinite array, it would not fit into the finite amount of memory your computer has….You could use:

1. int[] b = new int[a. length + 1];
2. for (int i=0; i < a. length; ++i) {
3. b[i] = a[i];
4. }
5. a = b;

int size means that size is a variable and C does not allow variable size arrays.

Here the first THREADBLOCK_SIZE elements of our shared memory array contain all 0-index elements of the private arrays for all threads of the thread block. The next THREADBLOCK_SIZE elements of the shared memory array contain all 1-index elements of the private arrays, and so on.

What You need to do is to find a symbol (can be constant) in Your device code, using ‘cudaGetSymbolAddress’ (say ‘dev_a’). Next copy the address of the allocated memory block (‘array’) to the address of the symbol You got with ‘cudaGetSymbolAddress’ call, i.e. copy it into the memory place where the ‘dev_a’ pointer is.

CUDA arrays are only readable by kernels through texture fetching and may only be bound to texture references with the same number of packed components. Allocating a CUDA array requires the specification of a channel format description matching the one used by the texture that needs to be mapped on it.

I changed it but I am getting a compiler error:”error: constant value is not known”. I’ve looked into it and it’s similar to this thread. So I tried: Thanks, Dan Update with code (pretty much followed this guide and the staring out with cuda guide): The block size is passed in by asking the user of the size of the matrix. They enter the x and y.