¿Cómo obtener el nombre del archivo de la URL?

How to get the file name from the URL?

This snippet will get the filename from the url. The filename is the last part of the URL from the last trailing slash. For example, if the URL is http://www.example.com/dir/file.html then file.html is the file name. This declares the url variable and adds the current pathname as its value.

How to get file input by selected file name without path using jQuery ? The task is to get the file input by selected filename without the path using jQuery. To select the file we will use HTML . After that we will get the file name by using the jQuery change () method.

Install the path package by adding it to the dependencies section in the pubspec.yaml file: The path package provides 3 useful functions that can help us get the filename or extension easily: You can get the same result with a file from the internet with its URL instead of a local path:

the file name is the part of the url after the last slash. the file extension is the part of the file name after the last period. – Sietse Jun 12 ’12 at 10:59 Instead of reinventing the wheel, how about using Apache commons-io: In version commons-io 2.2 at least you still need to manually handle URLs with parameters.

You can access it from http://127.0.0.1:8000/ Open your desired file in browser and copy the link to your url. Thanks for contributing an answer to Stack Overflow!

Requests doesn’t support local url. The easiest way seems using requests-file. “Requests-File is a transport adapter for use with the Requests Python library to allow local filesystem access via file:// URLs.” In a recent project, I’ve had the same issue.

The filename is the last part of the URL from the last trailing slash. For example, if the URL is http://www.example.com/dir/file.html then file.html is the file name.