¿Cómo se encuentra el registro distinto según la fecha máxima?

How do you find the distinct record based on maximum date?

If you need ID and Date columns with maximum date, then simply do a Group By on ID column and select the Max Date. If you need all the columns but 1 line having Max. date then you can go with ROW_NUMBER or MAX as mentioned in other answers.

COUNT DISTINCT does not count NULL as a distinct value. The ALL keyword counts all non-NULL values, including all duplicates. ALL is the default behavior if no keyword is specified.

To find the max value of a column, use the MAX() aggregate function; it takes as its argument the name of the column for which you want to find the maximum value. If you have not specified any other columns in the SELECT clause, the maximum will be calculated for all records in the table.

You might be able to solve this to set a “dummy” value to the NULL value. This way you can select the NULL value as the highest date. select CASE WHEN MAX(COALESCE(Date, 1000000)) = 1000000 THEN NULL ELSE MAX(Date) END as Date from Table T2 where T1.id= T2.id

SELECT TOP I see now the reason… In Option 2 the ordering is done for the secondary sort field. The WHERE clause selects rows only for a single day while ORDER BY + TOP causes the highest TransId within that day to be returned . The content must be between 30 and 50000 characters.

It should be: WITH x AS ( SELECT A, MAX (col_date) m FROM TABLENAME **group by A**) SELECT A, date FROM TABLENAME t JOIN x ON x.A = t.A AND x.m = t.col_date – EAmez Oct 8 ’18 at 12:52 SELECT t.* FROM TABLENAME t JOIN ( SELECT A, MAX(col_date) AS col_date FROM TABLENAME GROUP BY A ) m ON m.A = t.A AND m.col_date = t.col_date

How can I SELECT rows with MAX (Column value), DISTINCT by another column in SQL? I need to select each distinct home holding the maximum value of datetime. Doesn’t work. Result-set has 130 rows although database holds 187. Result includes some duplicates of home. Nope. Gives all the records. With various results.

Just replace ‘tablename’ with the name of your table, and ‘primaryidfield’ with the name of your primary ID field and it will give you the most recent record.

The LIMIT clause can be used to constrain the number of rows returned by the SELECT statement. SELECT * FROM permlog WHERE id = ( SELECT MAX(id) FROM permlog ) ; This would return all rows with highest id , in case id column is not constrained to be unique.

Remarks. The minimum valid date for a SqlDateTime structure is January 1, 1753.

SELECT group, date, checks FROM ( SELECT *, max_date = MAX(date) OVER (PARTITION BY group) FROM table ) AS s WHERE date = max_date ; to get the desired result. Basically, this is similar to @Twelfth’s suggestion but avoids a join and may thus be more efficient. You can try the method at SQL Fiddle.

Using the above output as a derived table, you can then get only rows where date matches max_date: to get the desired result. Basically, this is similar to @Twelfth’s suggestion but avoids a join and may thus be more efficient. You can try the method at SQL Fiddle.

MAX() function on date. In this part, you will see the usage of SQL MAX() function on date type of the column of a table. Example: Sample table: orders. To get the maximum ‘ord_date’ from the ‘orders’ table, the following SQL statement can be used : SELECT MAX (ord_date) AS “Max Date” FROM orders;

Records of different date ranges by using DATE_SUB (), CURDATE () and BETWEEN () query. Records of different date ranges by using DATE_SUB (), CURDATE () and BETWEEN () query. If playback doesn’t begin shortly, try restarting your device.

Find MAX value from multiple columns in a SQL Server table

1. Solution 1. The first solution is the following:
2. Solution 2. We can accomplish this task by using UNPIVOT:
3. Solution 3. This task can be solved by using UNION:
4. Solution 4. And the fourth solution also uses a UNION:
5. Performance Comparison.
6. Conclusion.

Example : SELECT with DISTINCT on all columns of the first query. To get the identical rows (on four columns agent_code, ord_amount, cust_code, and ord_num) once from the orders table , the following SQL statement can be used : SQL Code:

Try the Query below, which just adds TRUNC () to your date column before taking a DISTINCT of it. This is because the time factor in your column data is not the same. The query will actually reveal it.

If you need ID and Date columns with maximum date, then simply do a Group By on ID column and select the Max Date. If you need all the columns but 1 line having Max. date then you can go with ROW_NUMBER or MAX as mentioned in other answers.

If the SELECT clause contains more than one field, the combination of values from all fields must be unique for a given record to be included in the results. The output of a query that uses DISTINCT is not updateable and does not reflect subsequent changes made by other users. Omits data based on entire duplicate records, not just duplicate fields.

Filter for unique values or remove duplicate values

1. To filter for unique values, click Data > Sort & Filter > Advanced.
2. To remove duplicate values, click Data > Data Tools > Remove Duplicates.
3. To highlight unique or duplicate values, use the Conditional Formatting command in the Style group on the Home tab.

It means that DISTINCT does not take any effects in the MAX () function. Notice that DISTINCT has effects in other aggregate functions such as COUNT (), SUM (), and AVG (). We’ll use the payments table in the sample database to demonstration the MAX () function.

If record has a combination of duplicate id, addr and Ind, then select the max (update_date) from that record. If record has a combination of duplicate id, addr, Ind and update_Date, select only one record from the duplicate records (It can be any record). Below was the expected result. Can anyone plug me some ideas to achieve this.